4 Comments

I was wondering why you didn't take the geometric mean, as Guy mentioned upthread -- intuitively you'd expect the *log* of country population to be evenly distributed, since assuming the (non-log-transformed) country pops to be evenly distributed doesn't make much sense when the endpoints are a rounding error away from zero on one end and China on the other. You would've basically nailed this Fermi exercise. Of course that's not a straightforwardly generalizable takeaway though.

But there is a generalizable takeaway from this ostensible nitpick (I think), which is to familiarize yourself with lots of real-world examples of distributions. The "strategy" here is mainly broad reading plus doing frequent little Fermi estimates from time to time.

Just to not sound like a party-pooper I'd like to balance out my comment by saying I enjoyed your post, and I'd like to share a related article: https://forum.effectivealtruism.org/posts/3hH9NRqzGam65mgPG/five-steps-for-quantifying-speculative-interventions

It's by a Good Judgment superforecaster, Nuno Sempere. I thought it was a cool look into how a world-class estimation guy does his thing, even if his methods are way too effortful for me.

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Thanks for the link!

The honest answer to why I didn't use the geometric mean is that I simply didn't think of it at the time. It was obvious as soon as it was pointed out, but generally speaking when I use this method in practice, I pick one of the endpoints, and if I want to pick somewhere in the middle I use a more complex modelling process, so going from a plausible range to a point estimate in the middle isn't something I've put a great deal of thought into, and as such my advice there is/was imperfect.

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I will usually take the geometric mean when estimating magnitudes like this.

[100K, 15M] ==> 1.2M

[3M, 25M] ==> 8.6M

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Hmm. Yeah you're right, that's actually a very good idea. I'll have a think about it, but I might update this to be my default strategy, thanks. If so I'll update the article and give credit.

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